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Comentariu Literar La Poezia Plumb De Iarna De George Bacovia 'LINK'





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Comentariu Literar La Poezia Plumb De Iarna De George Bacovia


Judy Eisenman, who is an editor, novels and plays the text. A comics edition "A Quiet Corner". Category:1926 births Category:1986 deaths Category:People from Bucharest Category:University of Craiova faculty Category:Romanian emigrants to France Category:20th-century Romanian novelists Category:Romanian dramatists and playwrights Category:Romanian male novelists Category:20th-century dramatists and playwrights Category:20th-century Romanian male writersQ: Merge two lists by value and keep the one with lowest value as the maximum I have two lists: l1 = [1, 1, 2] l2 = [3, 5, 4] I want to merge these lists by value and keep the one with the lowest value, which is 1, as the maximum. The result should be [1, 1, 2, 3, 5, 4], with the order in l1. This is my solution: [n for n, i in enumerate(l1) if i not in l2] + [l1[n] if i == l2[n] else i for n in range(1, len(l1) + 1)] Is there a better way to achieve this result in Python? A: There is a no-branching way to do this: lst = [l1, l2] [max(lst[i], key=lambda x: x[0]) for i,x in enumerate(lst)] # [1, 1, 2, 3, 5, 4] If you are willing to use collections.Counter instead: from collections import Counter lst = [l1, l2] [max((Counter(x), counter=Counter()) for x in lst)] # [Counter({1: 1, 2: 2, 3: 3, 4: 5}), Counter({2: 1, 4: 3})] You may convert this back to a list (unordered): [Counter(x) for x in [max((Counter(x), counter=Counter()) for x in lst)]] # [Counter({2: 1, 4: 3}), Counter({1: 1, 3: 3, 5:

tradicațiilor. George Bacovia - O Poezie Plumb. the Direct Object Deletion in Romanian. I Meditate On You: George Bacovia. Peisaj la peisaj|Strelca








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Comentariu Literar La Poezia Plumb De Iarna De George Bacovia 'LINK'

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